Raul Ramirez defeated Fred Stolle 8-6 6-1 in the 1973 New Delhi quarterfinal on hard courts.
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Raul Ramirez | Fred Stolle |
|---|
| Country |
MEX
|
AUS
|
|---|
| Birth date | Jun 20, 1953 | Oct 8, 1938 |
|---|
| Age | 20 | 35 |
|---|
| Height | 183 cm | 190 cm |
|---|
| Handedness | Right-Handed | Right-Handed |
|---|
| Backhand style | One-Handed Backhand | — |
|---|
| Ranking (entering) | 32 | 40 |
|---|
| Ranking points (entering) | — | — |
|---|
| Elo (entering) | 1,765 | 1,834 |
|---|
| Current career W-L | 530–256 | 177–167 |
|---|
| Current career earnings | $2,217,971 | $328 |
|---|
Path
Raul Ramirez's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|
|
Ramanathan Krishnan
| 6-1 6-4 | W | — | Match data | Oct 25, 1973 | R16 |
|
Tau Luu
| 6-0 6-0 | W | — | Match data | Oct 24, 1973 | R32 |
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