Alexander Volkov defeated Pete Sampras 7-5 6-4 in the 1993 Indian Wells Open round of 16 on hard courts.
Match Statistics
| Stat | Alexander Volkov | Pete Sampras |
|---|
| Aces | 6 | 9 |
|---|
| Double faults | 2 | 3 |
|---|
| First serve % | 48 | 49 |
|---|
| First serve points won % | 74 | 75 |
|---|
| Second serve points won % | 56 | 42 |
|---|
| Break points saved % | 50 | 56 |
|---|
| Break points converted % | 44 | 50 |
|---|
| Service points won % | 65 | 58 |
|---|
| Return points won % | 42 | 35 |
|---|
| Total points won % | 53 | 47 |
|---|
Player Comparison
| Field | Alexander Volkov | Pete Sampras |
|---|
| Country |
RUS
|
USA
|
|---|
| Birth date | — | Aug 12, 1971 |
|---|
| Age | — | 21 |
|---|
| Height | 188 cm | 185 cm |
|---|
| Handedness | Left-Handed | Right-Handed |
|---|
| Backhand style | — | One-Handed Backhand |
|---|
| Ranking (entering) | 22 | 2 |
|---|
| Ranking points (entering) | 1,149 | 3,241 |
|---|
| Elo (entering) | 1,883 | 2,116 |
|---|
| Current career W-L | 291–246 | 739–209 |
|---|
| Current career earnings | $3,362,840 | $43,280,489 |
|---|
Path
Alexander Volkov's path
Alexander Volkov's next match