Rod Laver def. Fred Stolle
6-3 5-7 9-7
Rod Laver defeated Fred Stolle 6-3 5-7 9-7 in the 1968 La Paz Ntl round robin on clay courts on October 27, 1968.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Rod Laver | Fred Stolle |
|---|---|---|
| Country | AUS | AUS |
| Birth date | Aug 9, 1938 | Oct 8, 1938 |
| Age | 30 | 30 |
| Height | 175 cm | 190 cm |
| Handedness | Left-Handed | Right-Handed |
| Backhand style | One-Handed Backhand | — |
| Ranking (entering) | — | — |
| Ranking points (entering) | — | — |
| Elo (entering) | 1,903 | 1,685 |
| Current career W-L | 570–145 | 177–167 |
| Current career earnings | $1,565,413 | $328 |
No prior-path match data is available for this tournament stage.