Byron Black def. Toby Mitchell
7-6 6-2 6-2
Byron Black defeated Toby Mitchell 7-6 6-2 6-2 in the 1999 Australian Open round of 128 on hard courts.
Match Information
Match Statistics
| Stat | Byron Black | Toby Mitchell |
|---|---|---|
| Aces | 5 | 4 |
| Double faults | 4 | 3 |
| First serve % | 71 | 77 |
| First serve points won % | 82 | 56 |
| Second serve points won % | 37 | 36 |
| Break points saved % | 86 | 54 |
| Break points converted % | 46 | 14 |
| Service points won % | 69 | 52 |
| Return points won % | 48 | 31 |
| Total points won % | 58 | 42 |
Player Comparison
| Field | Byron Black | Toby Mitchell |
|---|---|---|
| Country | ZIM | AUS |
| Birth date | Oct 6, 1969 | Aug 20, 1976 |
| Age | 29 | 22 |
| Height | 175 cm | — |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 28 | 248 |
| Ranking points (entering) | 1,237 | 162 |
| Elo (entering) | 1,734 | 1,491 |
| Current career W-L | 240–230 | 0–2 |
| Current career earnings | $5,159,775 | $53,242 |
No prior-path match data is available for this tournament stage.