Arthur Ashe def. Harold Solomon
6-1 6-4
Arthur Ashe defeated Harold Solomon 6-1 6-4 in the 1978 ATP Finals round robin on carpet courts on January 10, 1979.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Arthur Ashe | Harold Solomon |
|---|---|---|
| Country | USA | USA |
| Birth date | Jul 10, 1943 | Sep 17, 1952 |
| Age | 35 | 26 |
| Height | 185 cm | 168 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | One-Handed Backhand | Two-Handed Backhand |
| Ranking (entering) | 13 | 9 |
| Ranking points (entering) | — | — |
| Elo (entering) | 1,967 | 1,931 |
| Current career W-L | 792–256 | 566–328 |
| Current career earnings | $1,584,909 | $1,802,769 |
No prior-path match data is available for this tournament stage.