Byron Black def. Rodolphe Gilbert
6-1 6-0
Byron Black defeated Rodolphe Gilbert 6-1 6-0 in the 1993 Mexican Open round of 32 on clay courts.
Match Information
Match Statistics
| Stat | Byron Black | Rodolphe Gilbert |
|---|---|---|
| Aces | 3 | 2 |
| Double faults | 2 | 1 |
| First serve % | 53 | 27 |
| First serve points won % | 78 | 90 |
| Second serve points won % | 65 | 19 |
| Break points saved % | 100 | 44 |
| Break points converted % | 56 | 0 |
| Service points won % | 72 | 38 |
| Return points won % | 62 | 28 |
| Total points won % | 68 | 32 |
Player Comparison
| Field | Byron Black | Rodolphe Gilbert |
|---|---|---|
| Country | ZIM | FRA |
| Birth date | Oct 6, 1969 | Dec 12, 1968 |
| Age | 23 | 24 |
| Height | 175 cm | 183 cm |
| Handedness | Right-Handed | Left-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 112 | 73 |
| Ranking points (entering) | 384 | 557 |
| Elo (entering) | 1,567 | 1,674 |
| Current career W-L | 240–230 | 67–115 |
| Current career earnings | $5,159,775 | $1,143,269 |
No prior-path match data is available for this tournament stage.