Rod Laver defeated Fred Stolle 6-4 18-16 6-4 in the 1969 Australian Open quarterfinal on grass courts.
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Rod Laver | Fred Stolle |
|---|
| Country |
AUS
|
AUS
|
|---|
| Birth date | Aug 9, 1938 | Oct 8, 1938 |
|---|
| Age | 30 | 30 |
|---|
| Height | 175 cm | 190 cm |
|---|
| Handedness | Left-Handed | Right-Handed |
|---|
| Backhand style | One-Handed Backhand | — |
|---|
| Ranking (entering) | — | — |
|---|
| Ranking points (entering) | — | — |
|---|
| Elo (entering) | 1,919 | 1,799 |
|---|
| Current career W-L | 570–145 | 177–167 |
|---|
| Current career earnings | $1,565,413 | $328 |
|---|
Path
Rod Laver's path
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