Mike Belkin def. Bob Lutz
6-4 5-7 9-7
Mike Belkin defeated Bob Lutz 6-4 5-7 9-7 in the 1968 Milwaukee round of 16 on clay courts.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
Path
Mike Belkin's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Sherwood Stewart | 8-6 6-4 | W | — | Match data | Jul 18, 1968 | R32 |
| Anthony Bull | 6-4 6-4 | W | — | Match data | Jul 17, 1968 | R64 |
Mike Belkin's next match
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Clark Graebner | 1-6 1-6 2-6 | L | H2H | Match data | Jul 20, 1968 | QF |
Bob Lutz's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| William Brown | 6-1 6-1 | W | H2H | Match data | Jul 18, 1968 | R32 |
| Rudy Hernando | 6-4 6-1 | W | H2H | Match data | Jul 17, 1968 | R64 |