Zeljko Franulovic def. Jan Kodes
6-2 3-6 6-3
Zeljko Franulovic defeated Jan Kodes 6-2 3-6 6-3 in the 1970 ATP Finals round robin on carpet courts on December 9, 1970.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Zeljko Franulovic | Jan Kodes |
|---|---|---|
| Country | CRO | CZE |
| Birth date | Jun 13, 1947 | Mar 1, 1946 |
| Age | 23 | 24 |
| Height | — | 175 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | One-Handed Backhand | One-Handed Backhand |
| Ranking (entering) | — | — |
| Ranking points (entering) | — | — |
| Elo (entering) | 1,955 | 1,844 |
| Current career W-L | 410–307 | 471–276 |
| Current career earnings | $6,000 | $693,197 |
No prior-path match data is available for this tournament stage.