Florian Mayer def. Hyung-Taik Lee
6-4 6-1 4-6 6-4
Florian Mayer defeated Hyung-Taik Lee 6-4 6-1 4-6 6-4 in the 2006 Australian Open round of 128 on hard courts.
Match Information
Match Statistics
| Stat | Florian Mayer | Hyung-Taik Lee |
|---|---|---|
| Aces | 10 | 2 |
| Double faults | 3 | 4 |
| First serve % | 50.0% | 63.0% |
| First serve points won % | 78.0% | 51.0% |
| Second serve points won % | 43.0% | 52.0% |
| Break points saved % | 29.0% | 36.0% |
| Break points converted % | 64.0% | 71.0% |
| Service points won % | 61.0% | 51.0% |
| Return points won % | 49.0% | 39.0% |
| Total points won % | 55.0% | 45.0% |
Player Comparison
| Field | Florian Mayer | Hyung-Taik Lee |
|---|---|---|
| Country | GER | KOR |
| Birth date | Oct 5, 1983 | Jan 3, 1976 |
| Age | 22 | 30 |
| Height | 191 cm | 180 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 69 | 112 |
| Ranking points (entering) | 544 | 386 |
| Elo (entering) | 1,720 | 1,605 |
| Current career W-L | 227–251 | 121–156 |
| Current career earnings | $7,278,992 | $2,355,686 |
No prior-path match data is available for this tournament stage.