Stephane Huet def. Alex Calatrava
1-6 6-3 6-4
Stephane Huet defeated Alex Calatrava 1-6 6-3 6-4 in the 1998 Austrian Open Kitzbühel round of 64 on clay courts.
Match Information
Match Statistics
| Stat | Stephane Huet | Alex Calatrava |
|---|---|---|
| Aces | 7 | 5 |
| Double faults | 1 | 3 |
| First serve % | 44.0% | 62.0% |
| First serve points won % | 77.0% | 64.0% |
| Second serve points won % | 53.0% | 50.0% |
| Break points saved % | 43.0% | 56.0% |
| Break points converted % | 44.0% | 57.0% |
| Service points won % | 63.0% | 59.0% |
| Return points won % | 41.0% | 37.0% |
| Total points won % | 51.0% | 49.0% |
Player Comparison
| Field | Stephane Huet | Alex Calatrava |
|---|---|---|
| Country | FRA | ESP |
| Birth date | Apr 25, 1971 | Jun 14, 1973 |
| Age | 27 | 25 |
| Height | 180 cm | 190 cm |
| Handedness | Left-Handed | Right-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 287 | 89 |
| Ranking points (entering) | 133 | 544 |
| Elo (entering) | 1,447 | 1,555 |
| Current career W-L | 14–39 | 69–109 |
| Current career earnings | $529,583 | $1,335,933 |
No prior-path match data is available for this tournament stage.