Site data updated: 2026-05-28 18:14 UTC
John Van Lottum def. Wayne Arthurs#90
7-6(2) 7-6(7)
Match Information
| Date | Oct 14, 1999* |
|---|---|
| Tournament | Singapore |
| Category | ATP 250 |
| Surface | Hard |
| Round | R32 |
| Winner | John Van Lottum |
| Score | 7-6(2) 7-6(7) |
| Loser | Wayne Arthurs |
| Duration | 1h 46m |
No match stats are available for this match.
Pre-match Comparison
| Field | John Van Lottum | Wayne Arthurs |
|---|---|---|
| Country | NED | AUS |
| Birth date | Apr 10, 1976 | Mar 18, 1971 |
| Age | 23 | 28 |
| Height | — | 190 |
| Handedness | Right-Handed | Left-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | — | 90 |
| Ranking points (entering) | — | 534 |
| Elo (entering) | 1,609 | 1,670 |
| Career W-L | — | 122–152 |
| Career earnings | $1,188,163 | $3,687,809 |
No prior-path match data is available for this tournament stage.