Stan Smith def. Zeljko Franulovic
6-1 5-6 6-1
Stan Smith defeated Zeljko Franulovic 6-1 5-6 6-1 in the 1970 ATP Finals round robin on carpet courts on December 9, 1970.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Stan Smith | Zeljko Franulovic |
|---|---|---|
| Country | USA | CRO |
| Birth date | Dec 14, 1946 | Jun 13, 1947 |
| Age | 23 | 23 |
| Height | 193 cm | — |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | One-Handed Backhand | One-Handed Backhand |
| Ranking (entering) | — | — |
| Ranking points (entering) | — | — |
| Elo (entering) | 2,023 | 1,960 |
| Current career W-L | 652–287 | 410–307 |
| Current career earnings | $1,774,811 | $6,000 |
No prior-path match data is available for this tournament stage.