Karol Kucera def. Byron Black
6-4 3-6 6-4
Karol Kucera defeated Byron Black 6-4 3-6 6-4 in the 1999 Indian Wells Open round of 64 on hard courts.
Match Information
Match Statistics
| Stat | Karol Kucera | Byron Black |
|---|---|---|
| Aces | 12 | 3 |
| Double faults | 5 | 0 |
| First serve % | 52 | 63 |
| First serve points won % | 74 | 63 |
| Second serve points won % | 39 | 45 |
| Break points saved % | 58 | 40 |
| Break points converted % | 60 | 42 |
| Service points won % | 57 | 57 |
| Return points won % | 43 | 43 |
| Total points won % | 51 | 49 |
Player Comparison
| Field | Karol Kucera | Byron Black |
|---|---|---|
| Country | SVK | ZIM |
| Birth date | Mar 4, 1974 | Oct 6, 1969 |
| Age | 25 | 29 |
| Height | 188 cm | 175 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | Two-Handed Backhand | Two-Handed Backhand |
| Ranking (entering) | 12 | 28 |
| Ranking points (entering) | 2,160 | 1,164 |
| Elo (entering) | 1,882 | 1,743 |
| Current career W-L | 261–233 | 240–230 |
| Current career earnings | $5,061,125 | $5,159,775 |
No prior-path match data is available for this tournament stage.