Wayne Black def. Tim Henman
6-3 6-4
Wayne Black defeated Tim Henman 6-3 6-4 in the 1998 Indian Wells Open round of 64 on hard courts.
Match Information
Match Statistics
| Stat | Wayne Black | Tim Henman |
|---|---|---|
| Aces | 3 | 4 |
| Double faults | 2 | 5 |
| First serve % | 61 | 43 |
| First serve points won % | 72 | 68 |
| Second serve points won % | 48 | 48 |
| Break points saved % | 80 | 33 |
| Break points converted % | 67 | 20 |
| Service points won % | 63 | 57 |
| Return points won % | 43 | 37 |
| Total points won % | 55 | 45 |
Player Comparison
| Field | Wayne Black | Tim Henman |
|---|---|---|
| Country | ZIM | GBR |
| Birth date | Nov 14, 1973 | Sep 6, 1974 |
| Age | 24 | 23 |
| Height | 170 cm | 185 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 79 | 19 |
| Ranking points (entering) | 583 | 1,623 |
| Elo (entering) | 1,584 | 1,844 |
| Current career W-L | 53–83 | 469–263 |
| Current career earnings | $3,300,258 | $11,635,542 |
No prior-path match data is available for this tournament stage.