Brad Gilbert def. David Wheaton
6-4 4-6 6-3 7-6(5)
Brad Gilbert defeated David Wheaton 6-4 4-6 6-3 7-6(5) in the 1991 Australian Open round of 128 on hard courts.
Match Information
Match Statistics
| Stat | Brad Gilbert | David Wheaton |
|---|---|---|
| Aces | 20 | 15 |
| Double faults | 2 | 3 |
| First serve % | 64 | 72 |
| First serve points won % | 66 | 68 |
| Second serve points won % | 53 | 49 |
| Break points saved % | 73 | 50 |
| Break points converted % | 50 | 27 |
| Service points won % | 61 | 63 |
| Return points won % | 37 | 39 |
| Total points won % | 51 | 49 |
Player Comparison
| Field | Brad Gilbert | David Wheaton |
|---|---|---|
| Country | USA | USA |
| Birth date | Aug 9, 1961 | Jun 2, 1969 |
| Age | 29 | 21 |
| Height | 185 cm | 193 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | — | — |
| Ranking (entering) | 10 | 34 |
| Ranking points (entering) | 1,451 | 835 |
| Elo (entering) | 1,956 | 1,857 |
| Current career W-L | 506–276 | 231–190 |
| Current career earnings | $5,507,973 | $5,238,401 |
No prior-path match data is available for this tournament stage.