David Wheaton def. Taylor Dent
6-7(1) 7-5 6-1
David Wheaton defeated Taylor Dent 6-7(1) 7-5 6-1 in the 1998 Indianapolis round of 64 on hard courts.
Match Information
Match Statistics
| Stat | David Wheaton | Taylor Dent |
|---|---|---|
| Aces | 6 | 4 |
| Double faults | 9 | 10 |
| First serve % | 49 | 42 |
| First serve points won % | 72 | 65 |
| Second serve points won % | 54 | 47 |
| Break points saved % | 70 | 62 |
| Break points converted % | 38 | 30 |
| Service points won % | 63 | 55 |
| Return points won % | 45 | 37 |
| Total points won % | 54 | 46 |
Player Comparison
| Field | David Wheaton | Taylor Dent |
|---|---|---|
| Country | USA | USA |
| Birth date | Jun 2, 1969 | Apr 24, 1981 |
| Age | 29 | 17 |
| Height | 193 cm | 188 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | — | — |
| Ranking (entering) | 263 | 574 |
| Ranking points (entering) | 149 | 34 |
| Elo (entering) | 1,633 | 1,488 |
| Current career W-L | 231–190 | 152–140 |
| Current career earnings | $5,238,401 | $2,563,378 |
No prior-path match data is available for this tournament stage.