Helena Sukova def. Brenda Schultz-Mccarthy
6-3 6-4
Helena Sukova defeated Brenda Schultz-Mccarthy 6-3 6-4 in the 1989 Indian Wells Open round of 16 on hard courts on March 6, 1989.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Helena Sukova | Brenda Schultz-Mccarthy |
|---|---|---|
| Country | CZE | NED |
| Birth date | Feb 23, 1965 | Dec 28, 1970 |
| Age | 24 | 18 |
| Height | 188 cm | 188 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | One-Handed Backhand | One-Handed Backhand |
| Ranking (entering) | 5 | 38 |
| Ranking points (entering) | 97 | 25 |
| Elo (entering) | 2,125 | 1,756 |
| Current career W-L | 581–300 | 298–222 |
| Current career earnings | $6,391,245 | $2,632,740 |
Path
Helena Sukova's path
No prior matches in this tournament.
Helena Sukova's next match
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Jana Novotna | 6-1 7-6 | W | H2H | Match data | Mar 6, 1989 | QF |
Brenda Schultz-Mccarthy's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Robin White | 4-6 6-4 7-5 | W | H2H | Match data | Mar 6, 1989 | R32 |