Site data updated: 2026-05-28 18:14 UTC
Tatiana Panova def. Francesca Lubiani
6-4 6-4
Match Information
| Date | Jan 21, 1998* |
|---|---|
| Tournament | Australian Open |
| Category | Grand Slam |
| Surface | Hard |
| Round | R128 |
| Winner | Tatiana Panova |
| Score | 6-4 6-4 |
| Loser | Francesca Lubiani |
No match stats are available for this match.
Pre-match Comparison
| Field | Tatiana Panova | Francesca Lubiani |
|---|---|---|
| Country | RUS | ITA |
| Birth date | Aug 13, 1976 | Jul 12, 1977 |
| Age | 21 | 20 |
| Height | 154 | 168 |
| Handedness | Right-Handed | Left-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 95 | 61 |
| Ranking points (entering) | 280 | 436 |
| Elo (entering) | 1,475 | 1,589 |
| Career W-L | 130–196 | 27–51 |
| Career earnings | $1,561,661 | $421,264 |
No prior-path match data is available for this tournament stage.