Mary Pierce def. Anne-Gaelle Sidot
6-2 5-7 7-5
Mary Pierce defeated Anne-Gaelle Sidot 6-2 5-7 7-5 in the 1999 Hamburg Open round of 16 on clay courts.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Mary Pierce | Anne-Gaelle Sidot |
|---|---|---|
| Country | FRA | FRA |
| Birth date | Jan 15, 1975 | Jul 24, 1979 |
| Age | 24 | 19 |
| Height | 178 cm | 172 cm |
| Handedness | Right-Handed | Left-Handed |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 8 | 47 |
| Ranking points (entering) | 2,131 | 558 |
| Elo (entering) | 2,045 | 1,626 |
| Current career W-L | 465–218 | 90–125 |
| Current career earnings | $9,793,119 | $1,236,925 |
Path
Mary Pierce's path
No prior matches in this tournament.
Mary Pierce's next match
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Conchita Martínez | 6-4 6-4 | W | H2H | Match data | May 1, 1999 | QF |
Anne-Gaelle Sidot's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Irina Spirlea | 6-7 6-2 7-6 | W | H2H | Match data | Apr 29, 1999 | R32 |