Site data updated: 2026-05-28 18:14 UTC
Helena Sukova#8 def. Claudia Kohde Kilsch#31
7-5 6-3
Match Information
| Date | Oct 19, 1989* |
|---|---|
| Tournament | Zurich |
| Category | WTA 250 |
| Surface | Carpet |
| Round | R32 |
| Winner | Helena Sukova |
| Score | 7-5 6-3 |
| Loser | Claudia Kohde Kilsch |
No match stats are available for this match.
Pre-match Comparison
| Field | Helena Sukova | Claudia Kohde Kilsch |
|---|---|---|
| Country | CZE | — |
| Birth date | Feb 23, 1965 | Dec 11, 1963 |
| Age | 24 | 25 |
| Height | 188 | 187 |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | — | — |
| Ranking (entering) | 8 | 31 |
| Ranking points (entering) | 88 | 33 |
| Elo (entering) | 2,021 | 1,858 |
| Career W-L | 580–297 | 401–233 |
| Career earnings | $6,391,245 | $2,227,116 |
No prior-path match data is available for this tournament stage.