Site data updated: 2026-05-28 18:14 UTC
Tatiana Panova#74 def. Anne-Gaelle Sidot#46
7-6 7-6
Match Information
| Date | Apr 7, 1999* |
|---|---|
| Tournament | Amelia Island |
| Category | WTA 250 |
| Surface | Clay |
| Round | R64 |
| Winner | Tatiana Panova |
| Score | 7-6 7-6 |
| Loser | Anne-Gaelle Sidot |
No match stats are available for this match.
Pre-match Comparison
| Field | Tatiana Panova | Anne-Gaelle Sidot |
|---|---|---|
| Country | RUS | FRA |
| Birth date | Aug 13, 1976 | Jul 24, 1979 |
| Age | 22 | 19 |
| Height | 154 | 172 |
| Handedness | Right-Handed | — |
| Backhand style | Two-Handed Backhand | — |
| Ranking (entering) | 74 | 46 |
| Ranking points (entering) | 360 | 558 |
| Elo (entering) | 1,473 | 1,622 |
| Career W-L | 130–196 | 90–125 |
| Career earnings | $1,561,661 | $1,236,925 |
No prior-path match data is available for this tournament stage.