Site data updated: 2026-05-28 18:14 UTC
Vera Zvonareva#42 def. Paola Suarez#238
6-2 6-3
Match Information
| Date | Jan 5, 2006* |
|---|---|
| Tournament | Auckland |
| Category | WTA 250 |
| Surface | Hard |
| Round | R32 |
| Winner | Vera Zvonareva |
| Score | 6-2 6-3 |
| Loser | Paola Suarez |
No match stats are available for this match.
Pre-match Comparison
| Field | Vera Zvonareva | Paola Suarez |
|---|---|---|
| Country | RUS | ARG |
| Birth date | Sep 7, 1984 | Jun 23, 1976 |
| Age | 21 | 29 |
| Height | 172 | 170 |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | Two-Handed Backhand | Two-Handed Backhand |
| Ranking (entering) | 42 | 238 |
| Ranking points (entering) | 759 | 132 |
| Elo (entering) | 1,683 | 1,712 |
| Career W-L | 459–268 | 223–180 |
| Career earnings | $16,875,970 | $5,217,775 |
No prior-path match data is available for this tournament stage.