Site data updated: 2026-05-28 18:14 UTC
Sharon Walsh Pete def. Beth Norton
6-7 6-2 6-1
Match Information
| Date | Dec 6, 1978* |
|---|---|
| Tournament | Sydney |
| Category | WTA 250 |
| Surface | Grass |
| Round | R64 |
| Winner | Sharon Walsh Pete |
| Score | 6-7 6-2 6-1 |
| Loser | Beth Norton |
No match stats are available for this match.
Pre-match Comparison
| Field | Sharon Walsh Pete | Beth Norton |
|---|---|---|
| Country | — | USA |
| Birth date | Feb 24, 1952 | Jun 13, 1957 |
| Age | 26 | 21 |
| Height | 174 | — |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | — | — |
| Ranking (entering) | — | — |
| Ranking points (entering) | — | — |
| Elo (entering) | 1,653 | 1,778 |
| Career W-L | 300–340 | 62–93 |
| Career earnings | $751,138 | $106,173 |
No prior-path match data is available for this tournament stage.