H2H data updated: 2026-07-19 02:51 UTC
Pamela Austin vs Vera Komar H2H: 1-0
Pamela Austin holds a 1–0 lead over Vera Komar in their WTA head-to-head. They have met 1 times in main draws. Most recently, Pamela Austin won the 1975 Austin fourth round 6-4 6-4.
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H2H Match Log
| Date | Tournament | Category | Round | Surface | Winner | Score | Loser | Match |
|---|---|---|---|---|---|---|---|---|
| Jan 17, 1975* | Austin | WTA 250 | R16 | — | Pamela Austin | 6-4 6-4 | Vera Komar | Match data |
* Estimated match date where the exact historical date is unavailable.
Career Comparison
| Player | Current | Peak | Pts | Elo | W | L | Win % | GS | 1000 | Finals | 500 | 250 | Titles |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Pamela Austin | — | — | — | 1,567 | 37 | 90 | 29.1% | 0 | 0 | 0 | 0 | 1 | 1 |
| Vera Komar | — | — | — | 1,516 | 6 | 11 | 35.3% | 0 | 0 | 0 | 0 | 0 | 0 |
Career Progression by Age
Seasons are aligned by the age each player spent most of that calendar year. GS and Titles are cumulative career totals through that season.
| Pamela Austin | Vera Komar | ||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Yr | W-L | Win % | Rank | Elo | GS | Titles | Yr | W-L | Win % | Rank | Elo | GS | Titles |
| 1968 | 1–4 | 20.0% | — | 1,478 | 0 | 0 | 1973 | 1–2 | 33.3% | — | 1,491 | 0 | 0 |
| 1969 | 3–15 | 16.7% | — | 1,385 | 0 | 0 | 1975 | 2–3 | 40.0% | — | 1,479 | 0 | 0 |
| 1970 | 15–23 | 39.5% | — | 1,487 | 0 | 0 | 1976 | 0–2 | 0.0% | — | 1,460 | 0 | 0 |
| 1971 | 8–14 | 36.4% | — | 1,535 | 0 | 0 | 1977 | 3–4 | 42.9% | — | 1,463 | 0 | 0 |
| 1972 | 5–11 | 31.2% | — | 1,523 | 0 | 1 | — | — | — | — | — | — | — |
| 1973 | 1–10 | 9.1% | — | 1,466 | 0 | 1 | — | — | — | — | — | — | — |
| 1974 | 0–6 | 0.0% | — | 1,402 | 0 | 1 | — | — | — | — | — | — | — |
| 1975 | 4–7 | 36.4% | — | 1,417 | 0 | 1 | — | — | — | — | — | — | — |