Clark Graebner defeated John Alexander 7-5 6-4 in the 1973 U.S. Pro Tennis Championships quarterfinal on clay courts.
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Clark Graebner | John Alexander |
|---|
| Country |
USA
|
AUS
|
|---|
| Birth date | Nov 4, 1943 | Jul 4, 1951 |
|---|
| Age | 29 | 22 |
|---|
| Height | 188 cm | 190 cm |
|---|
| Handedness | Right-Handed | Right-Handed |
|---|
| Backhand style | — | — |
|---|
| Ranking (entering) | — | — |
|---|
| Ranking points (entering) | — | — |
|---|
| Elo (entering) | 1,843 | 1,823 |
|---|
| Current career W-L | 342–161 | 567–419 |
|---|
| Current career earnings | $1,500 | $1,214,079 |
|---|
Path
Clark Graebner's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|
|
Erik Van Dillen
| 6-4 6-1 | W | — | Match data | Jul 20, 1973 | R16 |
|
Paul Sullivan
| 6-1 6-2 | W | — | Match data | Jul 19, 1973 | R32 |
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