Rod Laver def. Bob Lutz
6-3 6-4
Rod Laver defeated Bob Lutz 6-3 6-4 in the 1968 Los Angeles Open round of 32 on hard courts.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | Rod Laver | Bob Lutz |
|---|---|---|
| Country | AUS | USA |
| Birth date | Aug 9, 1938 | Aug 29, 1947 |
| Age | 30 | 21 |
| Height | 175 cm | 180 cm |
| Handedness | Left-Handed | Right-Handed |
| Backhand style | One-Handed Backhand | — |
| Ranking (entering) | — | — |
| Ranking points (entering) | — | — |
| Elo (entering) | 1,855 | 1,720 |
| Current career W-L | 570–145 | 388–272 |
| Current career earnings | $1,565,413 | — |
Path
Rod Laver's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| John Norgauer | 6-0 6-3 | W | — | Match data | Sep 16, 1968 | R64 |
Rod Laver's next match
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Jim Osborne | 6-2 7-5 | W | H2H | Match data | Sep 18, 1968 | R16 |
Bob Lutz's path
No prior matches in this tournament.