John Alexander def. Harold Solomon
3-6 6-3 6-2
John Alexander defeated Harold Solomon 3-6 6-3 6-2 in the 1975 Fort Worth Wct quarterfinal on hard courts.
Match Information
Match Statistics
Our current data sources do not include detailed match statistics for this match.
Player Comparison
| Field | John Alexander | Harold Solomon |
|---|---|---|
| Country | AUS | USA |
| Birth date | Jul 4, 1951 | Sep 17, 1952 |
| Age | 23 | 22 |
| Height | 190 cm | 168 cm |
| Handedness | Right-Handed | Right-Handed |
| Backhand style | — | Two-Handed Backhand |
| Ranking (entering) | — | — |
| Ranking points (entering) | — | — |
| Elo (entering) | 1,856 | 1,937 |
| Current career W-L | 567–419 | 566–328 |
| Current career earnings | $1,214,079 | $1,802,769 |
Path
John Alexander's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Anand Amritraj | 6-3 6-1 | W | — | Match data | Feb 21, 1975 | R16 |
| Humphrey Hose | 6-1 6-4 | W | H2H | Match data | Feb 20, 1975 | R32 |
John Alexander's next match
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Cliff Drysdale | 6-3 7-6(4) | W | H2H | Match data | Feb 22, 1975 | SF |
Harold Solomon's path
| Opponent | Score | W-L | H2H | Match Data | Date | Round |
|---|---|---|---|---|---|---|
| Stan Smith | 6-1 6-1 | W | H2H | Match data | Feb 21, 1975 | R16 |
| Gerald Battrick | 2-6 6-4 7-5 | W | H2H | Match data | Feb 20, 1975 | R32 |