Site data updated: 2026-05-28 18:14 UTC
John Alexander def. William Durham
6-2 6-3
Match Information
| Date | Jan 14, 1971* |
|---|---|
| Tournament | Hobart |
| Category | ATP 250 |
| Surface | Hard |
| Round | R16 |
| Winner | John Alexander |
| Score | 6-2 6-3 |
| Loser | William Durham |
No match stats are available for this match.
Pre-match Comparison
| Field | John Alexander | William Durham |
|---|---|---|
| Country | AUS | — |
| Birth date | Jul 4, 1951 | — |
| Age | 19 | — |
| Height | 190 | — |
| Handedness | Right-Handed | — |
| Backhand style | — | — |
| Ranking (entering) | — | — |
| Ranking points (entering) | — | — |
| Elo (entering) | 1,819 | 1,479 |
| Career W-L | 579–422 | — |
| Career earnings | $1,214,079 | — |
No prior-path match data is available for this tournament stage.