H2H data updated: 2026-07-21 02:15 UTC

Robert Maud vs Julian Krinsky H2H: 2-0

Robert Maud holds a 2–0 lead over Julian Krinsky in their ATP head-to-head. Across 2 main-draw meetings, Robert Maud leads 2–0 on hard courts. Most recently, Robert Maud won the 1969 Durban final 7-6 4-6 6-1 6-4.

RSA Right-Handed 180 cm / 5'11"
H2H
2 0
2 main draw meetings

H2H Match Log

DateTournamentCategoryRoundSurfaceWinnerScoreLoserMatch
Apr 20, 1969* Durban ATP 250 F Hard Robert Maud 7-6 4-6 6-1 6-4 Julian Krinsky Match data
Apr 5, 1968* Johannesburg 1 ATP 250 R16 Hard Robert Maud 6-4 11-9 6-4 Julian Krinsky Match data

* Estimated match date where the exact historical date is unavailable.

Career Comparison

Player Current Peak Pts Elo W L Win % GS 1000 Finals 500 250 Titles
Robert Maud #326 #57 0 1,804 123 131 48.4% 0 0 0 0 3 3
Julian Krinsky 1,531 0 0 0 0 0 0

Career Progression by Age

Seasons are aligned by the age each player spent most of that calendar year. GS and Titles are cumulative career totals through that season.

Robert Maud Julian Krinsky
YrW-LWin %RankEloGSTitles YrW-LWin %RankEloGSTitles
1968 29–11 72.5% 1,699 0 2
1969 21–10 67.7% 1,703 0 3
1970 23–13 63.9% 1,704 0 3
1971 22–31 41.5% 1,688 0 3
1972 6–26 18.8% 1,604 0 3
1973 8–16 33.3% #73 1,576 0 3
1974 12–13 48.0% #62 1,638 0 3
1975 2–11 15.4% #178 1,595 0 3