H2H data updated: 2026-07-20 02:15 UTC
Robert Maud vs Quentin Pretorius H2H: 1-0
Robert Maud holds a 1–0 lead over Quentin Pretorius in their ATP head-to-head. Across 1 main-draw meeting, Robert Maud leads 1–0 on hard courts. Most recently, Robert Maud won the 1968 Bloemfontein third round 6-2 6-0.
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H2H Match Log
| Date | Tournament | Category | Round | Surface | Winner | Score | Loser | Match |
|---|---|---|---|---|---|---|---|---|
| Jan 11, 1968* | Bloemfontein | ATP 250 | R32 | Hard | Robert Maud | 6-2 6-0 | Quentin Pretorius | Match data |
* Estimated match date where the exact historical date is unavailable.
Career Comparison
| Player | Current | Peak | Pts | Elo | W | L | Win % | GS | 1000 | Finals | 500 | 250 | Titles |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Robert Maud | #326 | #57 | 0 | 1,804 | 123 | 131 | 48.4% | 0 | 0 | 0 | 0 | 3 | 3 |
| Quentin Pretorius | — | — | — | 1,500 | — | — | — | 0 | 0 | 0 | 0 | 0 | 0 |
Career Progression by Age
Seasons are aligned by the age each player spent most of that calendar year. GS and Titles are cumulative career totals through that season.
| Robert Maud | Quentin Pretorius | ||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Yr | W-L | Win % | Rank | Elo | GS | Titles | Yr | W-L | Win % | Rank | Elo | GS | Titles |
| 1968 | 29–11 | 72.5% | — | 1,699 | 0 | 2 | — | — | — | — | — | — | — |
| 1969 | 21–10 | 67.7% | — | 1,703 | 0 | 3 | — | — | — | — | — | — | — |
| 1970 | 23–13 | 63.9% | — | 1,704 | 0 | 3 | — | — | — | — | — | — | — |
| 1971 | 22–31 | 41.5% | — | 1,688 | 0 | 3 | — | — | — | — | — | — | — |
| 1972 | 6–26 | 18.8% | — | 1,604 | 0 | 3 | — | — | — | — | — | — | — |
| 1973 | 8–16 | 33.3% | #73 | 1,576 | 0 | 3 | — | — | — | — | — | — | — |
| 1974 | 12–13 | 48.0% | #62 | 1,638 | 0 | 3 | — | — | — | — | — | — | — |
| 1975 | 2–11 | 15.4% | #178 | 1,595 | 0 | 3 | — | — | — | — | — | — | — |