WTA Hanko 1968 Draw, Results & Schedule

Birgitta Lindstrom won the 1968 Hanko, defeating Tiiu Kivi 6-4 6-2 in the final. The WTA 250 event was played on clay courts in Hanko, from July 25 to July 31, 1968. The match log contains 7 recorded singles results for this edition.

Full tournament history →
Champion
def. Tiiu Kivi , 6-4 6-2
Dates
Jul 25 — Jul 31
Location
Hanko
Category
WTA 250
Surface
Clay
Prize money

Historical categories use documented modern equivalents where available; unresolved editions keep their recorded category. Mapping details.

Results

Match type

7 recorded singles results

Hanko 1968 match log
WinnerScoreLoserH2HMatch DataDateRound
F (1)
Birgitta Lindstrom 6-4 6-2 Tiiu Kivi H2H Match data Jul 31, 1968* F
SF (2)
Tiiu Kivi 9-11 6-3 6-2 Katarina Bartholdson H2H Match data Jul 30, 1968* SF
Birgitta Lindstrom 6-1 6-4 Tiiu Soome H2H Match data Jul 30, 1968* SF
QF (4)
Tiiu Kivi 6-3 3-6 6-2 Leena Mutanen H2H Match data Jul 30, 1968* QF
Katarina Bartholdson 6-4 6-4 L Piila H2H Match data Jul 30, 1968* QF
Tiiu Soome 5-7 6-1 6-3 Hilkka Hannula H2H Match data Jul 30, 1968* QF
Birgitta Lindstrom 6-3 6-2 A Kree H2H Match data Jul 30, 1968* QF

Tournament Records

The leading Open Era records for Hanko.

Most Finals

Champion or runner-up finishes. 2 players share this record.

Most Appearances

Editions with a recorded main-draw match. 5 players share this record.

  1. A Kree 1 appearance

Open Era main-draw singles records from 1968 onward. Ranking records begin where reliable entering rankings are available.

Recent Finals

Recent Hanko finals
WinnerScoreRunner-upH2HMatch DataSeasonSurface
Birgitta Lindstrom 6-4 6-2 Tiiu Kivi H2H Match data 1968 Clay

View full tournament history →

Frequently Asked Questions

Where is Hanko held?
Hanko is held in Hanko.
Who won the most recent Hanko?
The 1968 Hanko was won by Birgitta Lindstrom, who defeated Tiiu Kivi 6-4 6-2.
When was the first Hanko played?
The first edition of Hanko was held in 1968.
What surface is Hanko played on?
Hanko is played on clay courts.